We’re updating Ivy Maths.We apologise for any bugs while we make improvements. Thanks for your patience.
Ivy Maths
All topics

Year 10 Foundation · Simultaneous equations

Use one known value to find another

Learn how to solve a pair of simultaneous equations by graph, by elimination and by substitution, adjusting the equations first when you need to.

Definition

A pair of simultaneous equations is two equations that use the same two unknowns and are both true at the same time. One equation on its own has many possible answers: x + y = 10 works for 1 and 9, for 2 and 8, and for plenty more. The second equation pins the unknowns down to a single pair of values, and solving the pair means finding that one pair. You can find it from a graph, by combining the equations to remove one unknown, or by substituting one equation into the other.

Why Do I Have to Learn This?

Simultaneous equations solve two mysteries at once, like the price of two different snacks. They pop up whenever two things depend on each other.

Key Rules:

  • 1. When one value is already known, substitute it into either equation and solve what is left to find the other unknown.

Remember:

  • Same signs subtract, opposite signs add; then substitute back so you finish with both values, not just one.

Don’t Forget...

  • Adding the equations when the matching terms have the same sign. 2y + 2y makes 4y, so nothing is eliminated; terms with the same sign need a subtraction, and only opposite signs cancel when you add.
  • Multiplying only some of the terms when scaling an equation. The equation stays true only if every term on both sides is multiplied, including the number on the right-hand side.
  • Stopping after finding the first unknown. The solution is a pair of values, so substitute the value you found back into an equation to find the second, then check both in the equation you have not used yet.

Worked Example:

Solve the simultaneous equations 3x + 2y = 16 and x + 2y = 8.

Both equations contain 2y with the same sign, so subtract the second from the first: 3x - x = 2x and 16 - 8 = 8, giving 2x = 8.

Solve for x: x = 4.

Substitute x = 4 into x + 2y = 8: 4 + 2y = 8, so 2y = 4 and y = 2.

Check the pair in the other equation: 3 x 4 + 2 x 2 = 12 + 4 = 16. Correct.

Answer: x = 4 and y = 2

Why It Works:

Both equations are true for the same pair of values, so adding them, subtracting them, or multiplying one through by a number produces another equation that the pair still satisfies. Arranging this so one unknown cancels leaves a true equation in a single unknown, which ordinary solving handles. The graph says the same thing: each line shows every pair that fits one equation, so the crossing point is the only pair that fits both.

Another Example:

Solve the simultaneous equations 4x + 3y = 23 and 2x - y = 9.

No terms match yet, so multiply the whole second equation by 3: 6x - 3y = 27.

The y terms are now 3y and -3y, opposite signs, so add the equations: 10x = 50, giving x = 5.

Substitute x = 5 into 2x - y = 9: 10 - y = 9, so y = 1.

Check the pair in the first equation: 4 x 5 + 3 x 1 = 20 + 3 = 23. Correct.

Answer: x = 5 and y = 1

Animated Example:

2x + 5 = 17
Start

Free Use one known value to find another Worksheet

Download free worksheets and practise today.

Every download has a fresh set of questions.

Let’s Practise the Concept

Step 1 of 3

Put them in order

Tap the numbers from smallest to largest.

In order so far: nothing yet